A1.1 Data Distributions
A2 – Recursion and Financial Modelling
OA1 – Matrices
OA2 – Networks and Decision Mathematics
OA3 – Geometry and Measurement
1 of 2

1.1.13 Normal Distribution – Standardised Values/z-scores

Standardised Values/z-scores

  • The z-score refers to a number of standard deviations a point lies from the centre (i.e. a z-score of 1 refers to a point 1 standard deviation above the centre).
  • This provides a convenient way of comparing distributions with different spreads and comparing values within the same distribution in a more statistically meaningful way.
  • A point lying below the centre (i.e. with a lower x-value) will have a negative z-score.
  • The z-score can be calculated using the formula:

z=\frac{x-\bar{x}}{s}

Where x is the actual score, \bar{x} is the mean, and s is the standard deviation.

Example: using standard score to find percentages

Assume the height of a group of people was measured and found to be normally distributed with a mean of 1.5m and standard deviation of 0.1m. A standard normal distribution with z-score is shown below:

Picture 3

If we wanted to find the percentage of people below 1.7m, we could do so in the following way:

  1. Convert the value to an equivalent z-score using the formula: z=\frac{1.7-1.5}{0.1}=2
  2. Using the above diagram, sum the values of all percentages below z=2:

13.5+34+34+13.5+2.35+0.15=97.5 \%

Example: using z-scores to compare values

Using the same distribution (height with mean of 1.5m and standard deviation of 0.1m), we want to compare the heights of two people. Brent has a z-score of 0 and Jack has a z-score of -0.6.

Without converting these z-scores into the actual heights, we can say that Brent’s height is exactly average (1.5m), as this is what a z-score of 0 corresponds to, and that Jack’s height lies between 1.4m (z-score of -1) and 1.5m (z-score of 0), as -1<0.6<0. We can also say that Jack is shorter than Brent as 0.6<0.

We can also convert these z-scores into their actual heights. In order to do this, we will need to use the rearranged version of the z-score formula:

x=z s+\bar{x}

Applying this to Brent and Jack’s z-scores:

Brent’s actual height is: x=0 * 0.1+1.5=1.5 m

Jack’s actual height is: x=-0.6 * 0.1+1.5=1.44 m

Diagram of a Bell curve

Picture 1